Please use this identifier to cite or link to this item: http://www.repositorio.ufop.br/handle/123456789/12609
Title: Infinitely many solutions for a Hénon-type system in hyperbolic space.
Authors: Cunha, Patrícia Leal da
Lemos, Flávio Almeida
Keywords: Hénon equation
Variational methods
Issue Date: 2020
Citation: CUNHA, P. L. da; LEMOS, F. A. Infinitely many solutions for a Hénon-type system in hyperbolic space. Advances in Difference Equations, v. 2020, n. 29, jan. 2020. Disponível em: <https://advancesindifferenceequations.springeropen.com/articles/10.1186/s13662-019-2469-6>. Acesso em: 03 jul. 2020.
Abstract: This paper is devoted to studying the semilinear elliptic system of Hénon type ⎧⎩⎨⎪⎪−ΔBNu=K(d(x))Qu(u,v),−ΔBNv=K(d(x))Qv(u,v),u,v∈H1r(BN),N≥3,{−ΔBNu=K(d(x))Qu(u,v),−ΔBNv=K(d(x))Qv(u,v),u,v∈Hr1(BN),N≥3, in the hyperbolic space BNBN, where H1r(BN)={u∈H1(BN):u is radial}Hr1(BN)={u∈H1(BN):u is radial} and −ΔBN−ΔBN denotes the Laplace–Beltrami operator on BNBN, d(x)=dBN(0,x)d(x)=dBN(0,x), Q∈C1(R×R,R)Q∈C1(R×R,R) is p-homogeneous, and K≥0K≥0 is a continuous function. We prove a compactness result and, together with Clark’s theorem, we establish the existence of infinitely many solutions.
URI: http://www.repositorio.ufop.br/handle/123456789/12609
metadata.dc.identifier.doi: https://doi.org/10.1186/s13662-019-2469-6
ISSN: 1687-1847
metadata.dc.rights.license: This article is licensed under a Creative Commons Attribution 4.0 International License, which permits use, sharing, adaptation, distribution and reproduction in any medium or format, as long as you give appropriate credit to the original author(s) and the source, provide a link to the Creative Commons licence, and indicate if changes were made. The images or other third party material in this article are included in the article’s Creative Commons licence, unless indicated otherwise in a credit line to the material. If material is not included in the article’s Creative Commons licence and your intended use is not permitted by statutory regulation or exceeds the permitted use, you will need to obtain permission directly from the copyright holder. To view a copy of this licence, visit http://creativecommons.org/licenses/by/4.0/. Fonte: o próprio artigo.
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